2 grams of magnesium react with 1.12 grams of oxygen in a closed vessel the reactant which is an excess and its left amounts are

Asked by arushidabhade | 17th Aug, 2019, 10:24: PM

Expert Answer:

This Chemical reaction can be wriiten as equation as
2 Mg space space space space space plus space space space space space straight O subscript 2 space space space space space space space space space space space rightwards arrow space space space space space space space space space space 2 MgO

2 over 24 space space space space space space space space space space space space space space fraction numerator 1.12 over denominator 32 end fraction space space space
.083 space space space space space space space space space space space space space space.035
.083 minus fraction numerator.083 space over denominator 2 end fraction space space space space.035 minus.035 space space space space space space space space space space.035 cross times 2 space space space space space
So space Mg space is space in space excess space and space straight O subscript 2 space is space straight a space limiting space reagent.
Moles space of space Mg space left equals.083 minus fraction numerator.083 over denominator 2 end fraction equals.083 minus.0415 equals.0415 space moles
Ammount space of space Mg space left equals.0415 cross times 24 equals 0.996 space gram

Moles space of space MgO space formed equals.035 cross times 2 space space equals.070 space mole space space space

Answered by Ravi | 18th Aug, 2019, 01:52: PM