2=cosA+1.35cosB 0=sinA-1.35sinB Find value of A and B

Asked by  | 2nd Dec, 2012, 12:01: PM

Expert Answer:

from 2nd equation
sinA=1.35 sinB
or, (sinA)^2=1.8225(sinB)^2
or,1-(cosA)^2=1.8225(1-(cosB)^2)
or, 1.8225(cosB)^2=(cosA)^2+0.8225
 
Now from 1st equation
2-cosA=1.35 cosB
squaring both side
4+(cosA)^2-4cosA=1.8225(cosB)^2
 
Subtituting tha value of 1.8225 (cosB)^2 from the previous equation
4+(cosA)^2-4cosA=(cosA)^2+0.8225
or, cosA=0.794
 
Subtituting in the first equation we can find B also by taking inverse.

Answered by  | 3rd Dec, 2012, 10:49: PM

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