1.the sum of the numer. and the denom. is 4 more than twice the numer. if the numer. and the denom. r increased by 3, they r in the ratio 2:3 2.the sum of numer. nd denom. of a fraction is 2 less than twice the denom.if the denom. is increased by 1,the numer.becomes half of the denom. 3.x takes 3 hrs more than y to walk 30km,but if x doubles his pace,he is ahead of y by 3/2 hrs.find da speed

Kindly post one query at a time.

The solution to the first question is as follows:

Let the fraction be x / y.

ATQ,   x + y =  4 + 2x   =>     y = x + 4     -------(i)

          x/( y + 3)  =  2 / 3                         -------(ii)

Substituting the value of y from equation (i) in (ii) :

x / (x + 4 + 3)  =  2 / 3

=>    3x   =   2 ( x + 7)

=>    3x - 2x = 14

So,      x  =  14

Putting in (i) we get,

y = 14 + 4 =  18

Hence the required fraction is  14 / 18