1.the sum of the numer. and the denom. is 4 more than twice the numer. if the numer. and the denom. r increased by 3, they r in the ratio 2:3 2.the sum of numer. nd denom. of a fraction is 2 less than twice the denom.if the denom. is increased by 1,the numer.becomes half of the denom. 3.x takes 3 hrs more than y to walk 30km,but if x doubles his pace,he is ahead of y by 3/2 hrs.find da speed

Asked by  | 22nd Aug, 2011, 12:00: AM

Expert Answer:

Kindly post one query at a time.
The solution to the first question is as follows:
Let the fraction be x / y.
ATQ,   x + y =  4 + 2x   =>     y = x + 4     -------(i)
          x/( y + 3)  =  2 / 3                         -------(ii)
Substituting the value of y from equation (i) in (ii) :
x / (x + 4 + 3)  =  2 / 3
=>    3x   =   2 ( x + 7)
=>    3x - 2x = 14
So,      x  =  14
Putting in (i) we get,
y = 14 + 4 =  18
Hence the required fraction is  14 / 18

Answered by  | 22nd Aug, 2011, 09:54: PM

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