1.Find the ratio of the number of atoms present in 16g of O2 and 32g of O3.

2.Find the charge of 48g of Mg2+ ions in coulombs.

Asked by pb_ckt | 16th May, 2019, 02:40: PM

Expert Answer:

1. Given:
 
Mass of O2 = 16 gm
 
Mass of O3 = 32 gm
 
Molar mass of  O2 = 32 gm
 
Molar mass of  O3 = 48 gm
 
No. of moles of  O2 
 equals space 16 over 32

equals space fraction numerator 1 space over denominator 2 end fraction space mole space of space straight O subscript 2
 
No. of moles of  O3
 
equals 32 over 48

equals 2 over 3 space mole space of space straight O subscript 3
 
1 mole of any substance contains 6.022 × 1023 atoms
 
1/2  mole of O2 will contains =1 half cross times space 6.022 space cross times space 10 to the power of 23 space cross times 2
 
2/3moles of O3 will conatain = 2 over 3 cross times 6.022 cross times 10 to the power of 23 space cross times 3 space space atoms space
 
Ratio of the number of atoms present 
 
 
equals space fraction numerator 1 half cross times space 6.022 space cross times space 10 to the power of 23 space cross times 2 over denominator begin display style 2 over 3 cross times space 6.022 space cross times space 10 to the power of 23 space cross times 3 end style end fraction

equals space 1 half
 
The ratio of number of atoms is 1:2

Answered by Varsha | 16th May, 2019, 03:36: PM