1.an electrostatic field line cannot be discontinous.why?
2.a proton is placed in a uniform electric field directed along the positive X-axis.in which direction will it tend to move?
Asked by Shunmathi Gs | 30th Jun, 2014, 09:26: PM
1. An electrostatic field line is the path of a positively charged particle in an electric field.Electric field is always continuous(directed from higher to lower potential) and exist at all points around a charge distribution. Hence an electrostatic field line is a continuous curve and cannot have sudden breaks.
2. When a proton is placed in an uniform electric field ,the proton will tend to move along the positive X- axis in the direction of electric field.
Answered by Jyothi Nair | 1st Jul, 2014, 09:42: AM
- teach me
- In fig three point charges q,-2q are q are placed along the x axis. Show that the electric field at p along the y axis is E =(1/4×3.14×e knot)×(3qa^2/y^4),when y>>a.
- Fig shows a plastic ball of mass m suspended by a light string in a uniform field of intensity e.the ball comes in equilibrium at an angle thita .if ex and ey are the x component and y component of the electric field, find the charge on the ball and the tension in the string
- eletric field on the axis of charged ring and draw its diagram
- this one
- What is mobility
- sir infinite rod se toh uniform electirc field hogi toh dE toh zero ho jayega na ?
- Why is the electric field in a capacitor after introduction of dielectric= (sigma -sigma p)/ epsilon . Where sigma is surface charge density and sigma p is surface charge density of the polarised dielectric.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number