18.4 gram mixture of MgCO3 and CaCO3 produce 4.48 litre of CO2 at STP. Then calculate the amount of MgCO3 and CaCO3 in mixture

Asked by Anil | 12th May, 2017, 09:42: PM

Expert Answer:

Let the mass of CaCO3 =xg ,so the mass of MgCO3 = 1.84-xg
x gram of CaCO3 will give CaO = 56 x /100
similarly 1.84 -x g will give MgO = 40(1.84 -x)/ 84 g
Total mass =0.96g
so, 0.56 + 40(1.84 -x)/ 84 g =0.96
x= 1
% of CaCO3 = 1/1.84 = 54.35
% of MgCO= 100- 54.35 = 45.65  

Answered by Vaibhav Chavan | 13th May, 2017, 05:54: PM