16th ques

Asked by lovemaan5500 | 8th Dec, 2017, 05:53: PM

Expert Answer:

space Its space straight a space combustion space analysis space
space space space space space space space space space Acid space plus space straight O subscript 2 space rightwards arrow for blank of space CO subscript 2 space end subscript space plus space straight H subscript 2 straight O
space space space space space space space space 0.2 gm space space space space space space space space space space space space space space space 0.50 gm space space space space space 0.089 gm
All space straight C space converted space to space CO subscript 2
All space straight H space converted space to space straight H subscript 2 straight O
and space other space element space like space straight O space is space determined space by space substraction space

1 right parenthesis space Calculate space mass space of space straight C space in space 0.50 gms space of space CO subscript 2
Mass space of space straight C space equals space 12 space and space that space of space CO subscript 2 space is space 44
therefore space 22 over 44 cross times space 0.50 space equals space 0.14 space straight g space of space straight C
convert space to space amount space in space moles space left parenthesis straight n right parenthesis
therefore straight n space equals space fraction numerator 0.14 over denominator 12 end fraction space equals space 0.011 space mol space of space straight C
2 right parenthesis space calculate space mass space of space straight H space in space 0.089 space gms space of space straight H subscript 2 straight O
mass space of space straight H space equals space 1 space and space that space of space space straight H subscript 2 straight O space is space 18
therefore space 2 over 18 cross times 0.089 space equals space 0.0098 space gm space of space straight H
convert space to space amount space in space moles space left parenthesis straight n right parenthesis
therefore straight n equals space fraction numerator 0.0098 over denominator 1 end fraction equals 0.0098 space mol space of space straight H
3 right parenthesis space space Now comma space calculate space mass space of space straight O space in space 0.2 space gm space of space acid space by space substracting space mass space of space straight C space and space straight H
space space space space mass space of space straight O space equals space space mass space of space acid space minus space mass space of space straight C space minus mass space of space straight H
space space space space space space space space space space space space space space space space space space space space space equals space space 0.2 minus 0.14 minus 0.0098 space equals space 0.050 space gm space of space straight O
convert space to space amount space in space moles space left parenthesis straight n right parenthesis
therefore space straight n equals space fraction numerator 0.050 over denominator 16 end fraction equals space 0.00313 space mol space of space straight O
Now comma space we space have space space straight C equals 0.011 space mol space space space straight H equals 0.0098 space mol space space space space straight O equals space 0.00313 space mol
now space divide space each space amount space by space the space smallest space to space get space the space lowest space whole space no. space ratio
straight C equals space fraction numerator 0.011 over denominator 0.003 end fraction equals 3.67 space
straight H space equals space fraction numerator 0.010 over denominator 0.003 end fraction equals space 3.2 space equals space 3
straight O space equals fraction numerator 0.003 over denominator 0.003 end fraction equals space 1
we space get space comma space straight C subscript 3.6 end subscript straight H subscript 3 straight O subscript 1 space end subscript space multilying space it space with space 2 space we space get space our space emperical space formula space straight i. straight e. comma straight C subscript 7 straight H subscript 6 straight O subscript 2
Given space molecular space mass space of space cid space equals space 244 gm space
straight C subscript 7 straight H subscript 6 straight O subscript 2 space equals space left parenthesis 7 cross times 12 right parenthesis space plus space left parenthesis 6 cross times 1 right parenthesis space plus space left parenthesis 2 cross times 16 right parenthesis equals 122
therefore 244 space equals space straight n space cross times 122
straight n equals 244 over 122 space equals space space 2
therefore space by space multilying space empercal space formula space by space 2 space we space get space molecular space formula space straight i. straight e. comma space straight C subscript 14 straight H subscript 12 straight O subscript 4
molecular space formula space of space given space acid space is space space straight C subscript 14 straight H subscript 12 straight O subscript 4.

Answered by Varsha | 8th Dec, 2017, 06:46: PM