1.615 g of an anhydrous salt was placed in moist air . After a few days it was found to be 2.875 g . ASSUMING THAT complete hydration took place calculate the simplest formula of Hydrated Salt . I the Composition of anhydrous salt is Zn = 40.6% ; S=19.8 % ; O=39.6% . Complete answer with all steps

Zn  40.6     65     40.6/65=0.62      0.62/0.62=1 

S    19.8     32     19.8/32=0.62      0.62/0.62=1

O    39.6     16     39.6/16=2.47      2.47/0.62 =3.9 =4

 

 

ZnSO4

 

 

water present= 2.875-1.615=1.260

 

No. of moles of water= 1.260/18 =0.07

 

 

1.615  the number of water added =0.07 moles

161 g  the no of water=  0.07x1.615/161=7

 

ZnSO4.7H2O