1.615 g of an anhydrous salt was placed in moist air . After a few days it was found to be 2.875 g . ASSUMING THAT complete hydration took place calculate the simplest formula of Hydrated Salt . I the Composition of anhydrous salt is Zn = 40.6% ; S=19.8 % ; O=39.6% . Complete answer with all steps

Asked by  | 15th Apr, 2012, 03:49: PM

Expert Answer:

Zn  40.6     65     40.6/65=0.62      0.62/0.62=1 
S    19.8     32     19.8/32=0.62      0.62/0.62=1
O    39.6     16     39.6/16=2.47      2.47/0.62 =3.9 =4
 
 
ZnSO4
 
 
water present= 2.875-1.615=1.260
 
No. of moles of water= 1.260/18 =0.07
 
 
1.615  the number of water added =0.07 moles
161 g  the no of water=  0.07x1.615/161=7
 
ZnSO4.7H2O

Answered by  | 26th Apr, 2012, 12:40: AM

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