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Asked by smanishkumar2002 | 04 Aug, 2018, 08:34: PM
ΔABC is an isosceles with AB = AC
Consider the equations of lines AB and AC are 7x - y + 3 = 0 and x + y - 3 = 0
Solving these quations we get (0, 3)
BC is passing through (1, -10)
Slope of the line 7x - y + 3 = 0 is 7
Slope of the line x + y - 3 = 0 is -1
Let m be the slope of the line BC
angle B  = angle C
tanB = tanC

Answered by Sneha shidid | 06 Aug, 2018, 10:36: AM

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