150 cells are supplying maximum current to external resistance of 0.6 ohm.the e.m.f. of each cell is 2 volts and internal resistance is 0.1 ohm show the arrangement of cell connection and find the value of current applied
Asked by Hritwik mishra | 19th Aug, 2011, 07:37: PM
for maximum cyrrent, the emf should be maximum and hence the cells are connected in series.
Therefore, emf of the battery = 150 x 2 = 300 volts
total internal resistance of the batter = 150 x 0.1 = 15 ohm.
Total resistance of the circuit = 15 + 0.6 = 15.6 ohm
Now, current = tot. emf / tot. resistance = 300 / 15.6 = 19.2 Ampere
Answered by | 23rd Aug, 2011, 08:07: PM
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