13 no.
Asked by Harshhacker2580
| 28th Apr, 2020,
11:20: AM
Expert Answer:
if v is the speed of bead at A , then its kinetic energy = (1/2) m v2
Forces acting on the bead = -mg - k ( x - R )
first term on RHS is due to weight and second term is due to spring force when spring is elongated to a distance x.
R is adius of hoop and also equals to natural length of spring
Hence workdone W on the bead is given by
= mgR +(1/2) k R2
By work-energy theorem , (1/2) m v2 = ( m g R ) + (1/2) k R2
Hence velocity of bead at A , v = [ ( 2 g R ) + (k/m) R2 ]1/2
= mgR +(1/2) k R2
Answered by Thiyagarajan K
| 28th Apr, 2020,
04:07: PM
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