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11th physics ch 2 k=p^2/2m relative error    
Asked by Jigarvora18 | 15 Jul, 2019, 23:56: PM
answered-by-expert Expert Answer
kinetic energy K = (1/2)p2/m  ..........................(1)
 
where p is momentum and m is mass. Let us assume mass remains constant.
 
if we differentiate eqn.(1), we get, dK = p dp/m  .................(2)
 
by dividing eqn.(2) with eqn.(1), we get relative error,    dK/K   = 2 dp/p
Answered by Thiyagarajan K | 16 Jul, 2019, 11:10: AM

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