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? question number 20Given AnswerAnswer option ( a) Plz help!! Thanq
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Asked by jhajuhi19 | 14 May, 2020, 09:40: AM
answered-by-expert Expert Answer
space space space space space space space space space space space space space space space space space space space space space space space space space space space 2 SO subscript 2 space plus space space space straight O subscript 2 space space space left right double arrow space 2 SO subscript 3 Initial space moles space space space space space space space space 1.5 space space space space space space space space space space space space 1 space space space space space space space space space space space space space space 0 Final space moles space space space space space space space space space space 1.5 minus 2 straight x space space 1 minus straight x space space space space space space space space space 2 straight x Concentration space of space SO subscript 3 space at space equilibrium space equals 0.35 space mole divided by straight L space space left parenthesis given right parenthesis space space space space space 2 straight x equals 0.70 space space space space space space space straight x equals 0.35 space mole divided by straight L straight K subscript straight c equals fraction numerator open square brackets SO subscript 3 close square brackets squared over denominator open square brackets SO subscript 2 close square brackets squared cross times open square brackets straight O subscript 2 close square brackets end fraction equals fraction numerator open square brackets 2 straight x close square brackets squared over denominator open square brackets 1.5 minus 2 straight x close square brackets squared cross times open square brackets 1 minus straight x close square brackets end fraction equals fraction numerator open square brackets fraction numerator 0.7 over denominator 2 end fraction close square brackets over denominator open square brackets begin display style fraction numerator 1.5 minus 0.7 over denominator 2 end fraction end style close square brackets open square brackets begin display style fraction numerator 1 minus 0.35 over denominator 2 end fraction end style close square brackets end fraction straight K subscript straight c equals 2.35 space straight L space mol to the power of negative 1 end exponent
Answered by Ravi | 14 May, 2020, 19:26: PM

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