CBSE Class 10 Answered
10 years ago father was 12 times as old as his son and 10 years hence he will be twice as old as his son. Find their present ages.
Asked by miniprasad | 04 May, 2018, 07:59: PM
Expert Answer
Let,
the Present age of the Son = x years
the Present age of the Father = y years
the Present age of the Son = x years
the Present age of the Father = y years
Acocording to the Conditions,
y - 10 = 12 ( x - 10) → 12x - y = 110...............1)
y + 10 = 2 ( x + 10 ) → 2x - y = -10 ................2)
Subtracting 2) from 1), we get
x = 12
Substituting the value of x = 12 in equation 2), we get
y = 34
y - 10 = 12 ( x - 10) → 12x - y = 110...............1)
y + 10 = 2 ( x + 10 ) → 2x - y = -10 ................2)
Subtracting 2) from 1), we get
x = 12
Substituting the value of x = 12 in equation 2), we get
y = 34
Therefore the Present age of Son and Father is 12 years and 34 years respectively.
Answered by Yasmeen Khan | 04 May, 2018, 10:19: PM
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