10 ml solution of nacl and kcl on evaporation give 0.93g of mix salt which gives 1.85g og AgCl by reacting with AgNO3 solution.Calculate the weight of nacl in the sample.

 

Given:

Mass of NaCl + Mass of KCl = 0.93 g

Let, x = grams of NaCl in original 10 ml solution mixture. Therefore, (0.93 - x) = grams of KCl in original mixture will be,

 (x) + (0.93 - x) = 0.93 g

 

So, the total mass of AgCl produced will be,

2.45 x + 1.92(0.93 - x) = 1.865

2.45 x + 1.785 - 1.92x = 1.865

0.53 x = 0.08

or, x = 0.150 g

Therefore, mass of NaCl = 0.15g

and mass of KCl = 0.93-x =0.93-0.15 = 0.78 g

Therefore, quantity of NaCl = 0.15 g