ICSE Class 10 Answered
10 g of mixture of NaCl and anhydrous sodium sulphate is dissolved in water.An excess of barium chloride solution is added and 6.99g of barium sulphate is ppt according to equation Na2SO4+BaCL2=BaSO4+2NaCL. CALCULATE the percentage of Na2SO4 IN THE ORIGINAL MIXTURE.
Asked by SUNITA | 22 Jul, 2013, 12:38: PM
Expert Answer
If there are 233 gm of Barium sulphate so Na2SO4 will be 142 gm. In the mixture 6.99 gm is Barium Sulphate So Na2SO4 will be 4.26 gms.
So % of Na2SO4 = (4.26 *100/ (10 + 4.26 )) = 29.87%
Answered by | 01 Sep, 2013, 08:24: AM
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