1. What is work done in moving a charge of 10 microcoulomb between two points on an equatorial surface?
2. An electric dipole odf dipole moment 20x10 to the power of minus 6Cm is kept in an enclosed surface. What is the net flux coming out of surface?
3. An electric dipole when held at 30 with respect to a uniform electic field of 10 to the power of 4 N/C experiences a torque of 9x 10 to the power of minus 26 Nm. Calculate the dipole moment.
4. If an oil drop of weight 3.2x 10 to the power of mimus 13 N is balanced in an electric field of strenght 5x10 to the power of 5 V/m. Find the charge on the oil drop.

Asked by JASKAMAL KAUR | 28th May, 2015, 10:13: AM

Expert Answer:

1. Equipotential surfaces are surfaces having same potential at every point on its surface. As the potential at two points on an equipotential surfaces is same, the work done in moving a charge of 10 μ C from any point on the equipotential surface to any other point on the equipotential surface is zero.

2. According to Gauss law we know that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permitivity.
i.e. 
begin mathsize 14px style straight ϕ equals straight q subscript enclosed over straight epsilon subscript 0 Charge space enclosed space by space the space closed space surface space is space minus straight q plus straight q space equals 0 Therefore space the space net space flux space coming space out space of space the space surface colon straight ϕ equals 0 over straight epsilon subscript 0 straight ϕ equals 0 end style
Thus the net flux out of the surface is zero.
 
Note: Please ask other questions as seperate seperate queries.

Answered by Jyothi Nair | 28th May, 2015, 01:09: PM

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