1) What is the force experienced by a positively charged particle Q moving at right angle to an uniform electric field? 

2) What is the effect on the charge on the plates of the capacitance on inserting dielectric in a parallel plate capacitors? 

Asked by hitanshu04 | 18th May, 2021, 07:05: PM

Expert Answer:

Force on charge = ( q E )
 
Where q is charge magnitude and E is electric field intensity .
 
Direction of force is in the direction of electric field
 
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If potential difference is not applied across capacitor plates while inserting dielectric material  ,
charge remains same after inserting dielectric material between capacitor plates.
 

If potential difference is  applied across capacitor plates while inserting dielectric material  ,
capacitance of capacitor increases by a factor K , where K is dielectric constant .
Since charge Q on capacitor plates is directly proportional to capacitance , charge is multiplied by a factor K 
after inserting dielectric material between capacitor plates.




Answered by Thiyagarajan K | 19th May, 2021, 09:23: AM