[(1+sinA-cosA) / (1+sinA+cosA)]^2 = (1-cosA) / (1+cosA)

Asked by dazzlerumix | 17th Sep, 2014, 05:59: PM

Expert Answer:

open square brackets fraction numerator 1 plus sin space A space minus space cos space A over denominator 1 plus sin space A space plus space cos space A end fraction close square brackets squared space equals space fraction numerator 1 plus space sin squared space A space plus space cos squared space A space plus 2 sin A space minus 2 cos A space minus space sin space 2 A space over denominator 1 plus space sin squared space A space plus space cos squared space A space plus 2 sin A space plus 2 cos A space plus space sin space 2 A end fraction  equals fraction numerator 2 space plus 2 sin A space minus 2 cos A space minus space 2 space sin space A space cos space A thin space over denominator 2 space plus thin space 2 sin A space plus 2 cos A space plus space 2 space sin space A space cos space A end fraction equals 2 over 2 cross times fraction numerator 1 space plus sin A space minus cos A space minus space sin space A space cos space A thin space over denominator 1 space plus thin space sin A space plus cos A space plus space sin space A space cos space A end fraction equals fraction numerator open parentheses 1 plus space sin space A close parentheses open parentheses 1 minus space cos space A close parentheses over denominator open parentheses 1 plus space sin space A close parentheses open parentheses 1 space plus cos space A close parentheses end fraction equals fraction numerator 1 minus space cos space A over denominator 1 space plus thin space cos space A end fraction  H e n c e space P r o v e d

Answered by Dharma Teja | 17th Sep, 2014, 07:06: PM

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