1)Show that for a body projected vertically up from the ground, the distance traveled by it in the last second of its upward motion is a constant independent of its initial velocity.
Asked by Shourya Mukherjee | 10th May, 2012, 10:00: PM
say s is the distance covered by the object in upward direction.
s=ut-1/2 gt2 =ut-5t2
distance covered in (t-1) sec=s'=u(t-1)-5(t-1)2
expand the prev identities.
so dist covered in last sec=s-s'=u-10t+5 ... (1)
so u=10t put this in equ 1:
so dist in last sec=10t-10t+5=5=constant
Answered by | 14th May, 2012, 04:40: PM
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