CBSE Class 11-science Answered
1 gram of mixture of carbonates of calcium and magnesium gave 240 cm^3 of carbon dioxide at S.T.P. Calculate the percentage composition of the mixture.
Asked by Manoj | 08 Jul, 2013, 08:33: PM
Expert Answer
1. Let the mass of CaCO3 in the mixture be X g.
Let the mass of MgCO3 in the mixture be (1 - X )g.
2. calculate volume of CO2 from CaCO3 -
CaCO3 ? CaO + CO2
100 g 22400 mL
100 g of CaCO3 forms 22400 mL of CO2
x g of CaCO3 forms 22400 x / 100 = 224 x mL.
3. calculate volume of CO2 from MgCO3 -
MgCO3 ? MgO + CO2
84 g 22400 mL
84 g of MgCO3 forms 22400 mL of CO2
(1 - x) g of MgCO3 forms 22400 (1 -x ) / 84 = 266.67 ( 1-x) mL.
4. To calculate %
Total CO2 evolved = 224 x mL + 266.67 ( 1-x) mL.
Actually 240 mL CO2 evolved ;
Hence 224 x mL + 266.67 ( 1-x) mL. = 240 mL
224x + 266.67 + 266.67x = 240
or x = 26.67 / 42.67
= 0.6250
thus % CaCO3 in the mixture = 0.6250 x 100
= 62.50 %
% MgCO3 in the mixture = 100 - 62.50
= 37.50 %
Answered by | 13 Jul, 2013, 12:55: AM
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