1 g mixture of cuprous and cupric oxides was reduced to 0.849 g metallic copper. What is the weight of cuprous oxide in sample

Asked by Anil | 13th May, 2017, 09:46: PM

Expert Answer:

Wt. of Cu2O and CuO = 1g

Wt. of CuO = x g

Hence Wt. of Cu2O = (1-x)g

Cu2O → 2Cu + ½ O2

CuO → Cu + ½ O2

Hence moles of Cu by principle of atom conservation

= 2x moles of Cu2O + moles of CuO

Moles of Cu2O = 1-x/143

Moles of CuO = x/79.5

Hence Moles of Cu = 2(1-x/143) + x/79.5

Weight of copper

2(1-x/143) x63.5 + x 63.5/79.5 = 0.849

2-2x/143 + x/79.5 =0.849/63.5

159 -159x + 143x = 0.849 x 143 x 79.5/63.5

-159 x + 143 x= 152 -159

16x =7

x = 0.437 g

Answered by Vaibhav Chavan | 15th May, 2017, 12:06: PM