1) Factorise by using middle term splitting

83 + 27y3 + z3 _ 18yz

2) Find

(783)2/3

Please explain step-by-step.

use cubic algebraic identities

Asked by stutagra | 26th May, 2016, 04:36: PM

Expert Answer:

1 right parenthesis 8 cubed plus 27 y cubed plus z cubed minus 18 y z equals 2 cubed plus open parentheses 3 y close parentheses cubed plus z cubed minus 3 open parentheses 2 close parentheses open parentheses 3 y close parentheses open parentheses z close parentheses equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus open parentheses 3 y close parentheses squared plus z squared minus 2.3 y minus 3 y. z minus 2 z close parentheses equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus 9 y squared plus z squared minus 6 y minus 3 y z minus 2 z close parentheses 2 right parenthesis 783 equals 3 cubed cross times 29 783 squared equals 3 to the power of 6 cross times 29 squared open parentheses 783 squared close parentheses to the power of 1 divided by 3 end exponent equals 3 to the power of 6 divided by 3 end exponent cross times 29 to the power of 2 divided by 3 end exponent equals 3 squared cross times 29 to the power of 2 divided by 3 end exponent

Answered by satyajit samal | 29th May, 2016, 04:24: PM

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