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CBSE Class 9 Answered

<p style="font-size: 11px;">1) Factorise by using middle term splitting</p> <p style="font-size: 11px;"><span style="font-size: 10px;">8<sup>3</sup>&nbsp;+ 27y<sup>3&nbsp;</sup>+ z<sup>3<span style="font-size: 10px;">&nbsp;_&nbsp;</span></sup><span style="font-size: 10px;">18yz</span></span></p> <p style="font-size: 11px;"><span style="font-size: 10px;">2)&nbsp;Find</span></p> <p style="font-size: 11px;"><span style="font-size: 10px;">(783)<sup>2/3</sup></span></p> <p><span style="font-size: 10px;">Please explain step-by-step.</span></p> <p><span style="font-size: 10px;">use cubic algebraic identities</span></p>
Asked by stutagra | 26 May, 2016, 04:36: PM
Expert Answer
1 right parenthesis
8 cubed plus 27 y cubed plus z cubed minus 18 y z
equals 2 cubed plus open parentheses 3 y close parentheses cubed plus z cubed minus 3 open parentheses 2 close parentheses open parentheses 3 y close parentheses open parentheses z close parentheses
equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus open parentheses 3 y close parentheses squared plus z squared minus 2.3 y minus 3 y. z minus 2 z close parentheses
equals open parentheses 2 plus 3 y plus z close parentheses open parentheses 2 squared plus 9 y squared plus z squared minus 6 y minus 3 y z minus 2 z close parentheses

2 right parenthesis
783 equals 3 cubed cross times 29
783 squared equals 3 to the power of 6 cross times 29 squared
open parentheses 783 squared close parentheses to the power of 1 divided by 3 end exponent equals 3 to the power of 6 divided by 3 end exponent cross times 29 to the power of 2 divided by 3 end exponent
equals 3 squared cross times 29 to the power of 2 divided by 3 end exponent
Answered by satyajit samal | 29 May, 2016, 04:24: PM
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