1. E is any point on median AD of a triangle ABC. Show that area of triangle ABE = area of triangle ACE.
Asked by | 5th Oct, 2010, 12:00: AM
Since, AD is the median of ΔABC, it will divide ΔABC into two triangles of equal areas.
∴ Area (ΔABD) = Area (ΔACD) ... (1)
Now, ED is the median of ΔEBC.
∴ Area (ΔEBD) = Area (ΔECD) ... (2)
From (1) and (2):
Area (ΔABD) − Area (EBD) = Area (ΔACD) − Area (ΔECD)
Therefore, Area (ΔABE) = Area (ΔACE)
We hope that clarifies your query.
Answered by | 5th Oct, 2010, 07:04: PM
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