1) Calculate the number of Cl2 molecules and Cl atoms in 0.25 mol of Cl2 gas.

2)  Molar mass of O is 16 g  mol-1. What is the mass of one atom and one molecule of Oxygen?

 

Asked by seeni2005 | 19th Feb, 2021, 12:52: PM

Expert Answer:

Number of molecules of Cl2 is calculated by-
left parenthesis 1 right parenthesis N u m b e r space o f space m o l e c u l e s space o f space C l subscript 2 space end subscript equals N u m b e r space o f space m o l e s space o f space C l subscript 2 cross times N subscript A
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.25 cross times 6.022 cross times 10 to the power of 23
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1.5055 cross times 10 to the power of 23 space m o l e c u l e s
space 1 space m o l e c u l e space o f space C l subscript 2 space h a s equals space 2 space C l space a t o
1.5055 cross times 10 to the power of 23 space m o l e c u l e s space o f space C l subscript 2 space w i l l space h a v e equals 1.5055 cross times 10 to the power of 23 cross times 2 equals 3.011 cross times 10 to the power of 23 space a t o m s

left parenthesis 2 right parenthesis space 1 space m o l e space o f space O space h a s space m a s s space o f space 16 space g space
W h c i h space m e a n s space 6.022 cross times 10 to the power of 23 a t o m s space o f space O space h a s equals space 16 space g space o f space m a s s
M a s s space o f space o n e space a t o m space o f space o x y g e n space equals fraction numerator 16 over denominator 6.022 cross times 10 to the power of 23 end fraction equals 2.656 cross times 10 to the power of negative 23 end exponent space g
m a s s space o f space 1 space m o l e space o f space o x y g e n space space equals 32 space g
W h i c h space m e a n s space m a s s space o f space 6.022 cross times 10 to the power of 23 space m o l e c u l e s space o f space O subscript 2 space i s equals 32 space g
M a s s space o f space 1 space m o l e c u l e space o f space O subscript 2 space w i l l space b e equals fraction numerator 32 over denominator 6.022 cross times 10 to the power of 23 end fraction equals 5.3138 cross times 10 to the power of negative 23 end exponent space g

Answered by Ravi | 20th Feb, 2021, 11:06: PM