1.p r o v e space t h a t C o t squared space theta left parenthesis s e c theta minus 1 right parenthesis divided by 1 plus sin theta equals s e c to the power of 2 space end exponent theta left parenthesis 1 minus sin theta divided by 1 plus s e c theta right parenthesis
2.begin mathsize 26px style open curly brackets 1 divided by s e c squared theta minus cos squared theta space plus space 1 divided by cos e c squared theta minus sin squared theta close curly brackets left parenthesis sin squared theta cos squared theta right parenthesis equals 1 minus sin squared theta cos squared theta divided by 2 plus sin squared theta cos squared theta end style

Asked by GURSHARNSUITS | 22nd Jul, 2015, 10:29: PM

Expert Answer:

P l e a s e space a s k space o n e space q u e s t i o n space i n space a space sin g l e space p o s t. 1. space L H S equals fraction numerator c o t squared theta open parentheses s e c theta minus 1 close parentheses over denominator 1 plus sin theta end fraction equals fraction numerator c o t squared theta open parentheses s e c theta minus 1 close parentheses open parentheses s e c theta plus 1 close parentheses over denominator open parentheses 1 plus sin theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator c o t squared theta open parentheses s e c squared theta minus 1 close parentheses over denominator open parentheses 1 plus s i n theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator c o t squared theta tan squared theta over denominator open parentheses 1 plus s i n theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator 1 over denominator open parentheses 1 plus s i n theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator 1 minus sin theta over denominator open parentheses 1 plus s i n theta close parentheses open parentheses 1 minus s i n theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator 1 minus s i n theta over denominator open parentheses 1 minus s i n squared theta close parentheses open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator 1 minus s i n theta over denominator cos squared theta open parentheses s e c theta plus 1 close parentheses end fraction equals fraction numerator s e c squared theta open parentheses 1 minus sin theta close parentheses over denominator open parentheses s e c theta plus 1 close parentheses end fraction equals R H S space left parenthesis P r o v e d right parenthesis

Answered by satyajit samal | 23rd Jul, 2015, 09:18: AM