0.8 mole of a mixture of CO and CO2 requires exactly 40 gm of NaOH in solution for complete conversion of all the CO2 ino Na2CO3. How many moles more of NaOH would it require for conversion into Na2CO3, if the mixture (0.8 mol) is completely oxidised to CO2.
Asked by medha painuly | 10th Jun, 2014, 06:52: AM
2 NaOH +CO2 --> Na2CO3 + H2O
1 mol CO2 requires 2 moles of NaOH
40 g NaOH = 1 mol NaOH
If 1 mole of NaOH is used up by 0.8 mol mixture of CO + CO2 , then the mixture must contain 0.5 mol of CO2. The rest 0.3 mol are of CO.
If these 0.3 mol of CO are also oxidised to CO2 , then 0.3 mol of CO2 would require 0.6 mol of NaOH.
Hence, 0.6 mol more of NaOH would it require for conversion into Na2CO3, if the mixture (0.8 mol) is completely ozxidised to CO2.
Answered by Prachi Sawant | 10th Jun, 2014, 11:29: AM
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