0.52 g gluoe is dissolved in 80.2 g of water, calcula the boiling point of the solution. (kb or water in 0.52kg mol^-1)
Asked by Sunny Acharjee | 3rd Mar, 2013, 07:54: PM
ΔTb = Kb x Wb x 1000 / Mb x WA.
Kb = 0.52 , WB = 0.52 g , Mb = 180g ( C6H12O6) , 80.2 g
ΔTb = answer of the above.
Boiling point of the solution = ΔTb ( the answer above) + 100 °( boiling point of water)
Answered by | 4th Mar, 2013, 08:06: PM
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