0.2% aqueous solution of a non-volatile solute produces a vapour pressure of 1.004bar at 100C. what is the molar mass of the solute?

Asked by Mayuri dave | 16th May, 2013, 06:57: PM

Expert Answer:

p0 - p/p  = nB /nA

1.013 - 1.004 / 1.004  = .2 x18 /Mb  x 98

   M  = .2 x 18 x 1.004  / .009 x 98

          = 3.6144 / .882

           =4.09 gmol-1

Answered by  | 23rd May, 2013, 07:28: PM

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