0.17g of ammonia on decomposition gave 0.14 g of nitrogen and rest hydrogen. What will be the volume of hydrogen evolved at S.T.P?
 

Asked by lekhakarthikeyan | 27th May, 2017, 11:48: PM

Expert Answer:

2NH3 → N2 + 3H2


Moles of NH3 present = 0.17 g x 1 mol/17 g = 0.01 moles 


moles H2 produced = 3/2 x 0.01 moles = 0.015 moles H2 


At STP 1 mole = 22.4 L

 

So volume of H2 = 0.015 moles x 22.4 L/mol = 0.336 Liters. 

Answered by Vaibhav Chavan | 28th May, 2017, 12:04: PM