0.17g of ammonia on decomposition gave 0.14 g of nitrogen and rest hydrogen. What will be the volume of hydrogen evolved at S.T.P?
Asked by lekhakarthikeyan | 27th May, 2017, 11:48: PM
Expert Answer:
2NH3 → N2 + 3H2
Moles of NH3 present = 0.17 g x 1 mol/17 g = 0.01 moles
moles H2 produced = 3/2 x 0.01 moles = 0.015 moles H2
At STP 1 mole = 22.4 L
So volume of H2 = 0.015 moles x 22.4 L/mol = 0.336 Liters.
2NH3 → N2 + 3H2
Moles of NH3 present = 0.17 g x 1 mol/17 g = 0.01 moles
moles H2 produced = 3/2 x 0.01 moles = 0.015 moles H2
At STP 1 mole = 22.4 L
So volume of H2 = 0.015 moles x 22.4 L/mol = 0.336 Liters.
Answered by Vaibhav Chavan | 28th May, 2017, 12:04: PM
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