# 01---- A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field, and energy associated with this capacitor are given by Q0, V0, E0 and U0 respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities are now given by Q, V, E and U are related to previous quantities as (a) Q> Q0 (b) V> V0 (c) E> E0 (d) U> U0 02---A parallel plate air capacitor with no dielectric between the plates is connected to the constant voltage source. How would capacitance and charge change if dielectric of dielectric constant K=2 is inserted between the plates. C0 and Q0 are the capacitance and charge of the capacitor before the introduction of the dielectric. (a) C=C0/2 ; Q=2Q0 (b) C=2C0 ; Q=Q0/2 (c) C=C0/2 ; Q=Q0/2 (d) C=2C0 ; Q=2Q0

### Answered by Faiza Lambe | 19th Nov, 2015, 02:06: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.

### STUDY RESOURCES

REGISTERED OFFICE : First Floor, Empire Complex, 414 Senapati Bapat Marg, Lower Parel, Mumbai - 400013, Maharashtra India.