0.05 cm thick coating of silver is deposited on a plate of 0.5

Asked by Ujjwal Kumar | 5th Oct, 2010, 08:46: PM

Expert Answer:

Dear Student,
 Assuming that the coating is uniform we will calculate the volume of deposited silver
        Volume= 0.05 cm × 5000 cm2 = 250 cm3
 
Since,                   Mass = Volume × density
mass of deposited silver = 250 cm3 × 7.9 g/cm3
                                   = 1975 g
Since we know 108 g silver has 6.022 ×1023  atoms of silver
Number of silver atoms in 1975 g =6.022 ×1023 ×1975⁄108
                                                = 110.12 × 1023   = 11.01 ×1024 atoms
We hope that clarifies your query
Regards,
Team
Topperlearning            

Answered by  | 6th Oct, 2010, 12:14: PM

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