0.05 cm thick coating of silver is deposited on a plate of 0.5

Dear Student,

 Assuming that the coating is uniform we will calculate the volume of deposited silver

        Volume= 0.05 cm × 5000 cm² = 250 cm³

 

Since,                   Mass = Volume × density

mass of deposited silver = 250 cm³ × 7.9 g/cm³

                                   = 1975 g

Since we know 108 g silver has 6.022 ×10²³  atoms of silver

Number of silver atoms in 1975 g =6.022 ×10²³ ×1975⁄108

                                                = 110.12 × 10²³   = 11.01 ×10²⁴ atoms

We hope that clarifies your query

Regards,

Team

Topperlearning