Archive
11th of April 2017
Mathematics
Q:

pqrs is a quadrilateral .a line through s parallel to pr meets qr produced in x show that ar pqrs ={triangle pxq}

Muralivenkatavarathan Muralivenkat - CBSE - Class IX

Tuesday, April 11, 2017 at 17:55:PM

A:

ΔPRS and ΔPRX are on the same base PR and between the same parallels as PR is parallel to SX.

So, ar(ΔPRS) = ar(ΔPRX)

On adding ar(ΔPQR) to both sides, we get

ar(ΔPRX) + ar(ΔPQR) = ar(ΔPRS) + ar(ΔPQR)

ar(ΔPQX) = ar(quad. PQRS)

Tuesday, April 11, 2017 at 18:02:PM