Question
Thu May 05, 2011 By: Akankshya Sahu
 

Why does focus of a spherical mirror does not depend on whether the rays are paraxial or not?

Expert Reply
Thu May 05, 2011
Spherical mirrors reflect non-paraxial rays, i.e. rays from the axis of the spherical surface, to a circular blur of points termed the circle of confussion.
A convex mirror, fish eye mirror or diverging mirror, is a curved mirror in which the reflective surface bulges toward the light source. Convex mirrors reflect light outwards, therefore they are not used to focus light. Such mirrors always form a virtual image, since the focus (F) and the centre of curvature (2F) are both imaginary points "inside" the mirror, which cannot be reached. Therefore images formed by these mirrors cannot be taken on screen. (As they are inside the mirror).

A concave mirror, or converging mirror, has a reflecting surface that bulges inward (away from the incident light). Concave mirrors reflect light inward to one focal point.They are used to focus light. Unlike convex mirrors, concave mirrors show different image types depending on the distance between the object and the mirror.

These mirrors are called "converging" because they tend to collect light that falls on them, refocusing parallel incoming rays, toward a focus. This is because the light is reflected at different angles, since the normal to the surface differs with each spot on the mirror.


            Let us first consider the image formed by a concave mirror of a point O on the axis.  It was assumed earlier that an optical device forms a sharp point image of a point object.  In the case of a concave mirror, this is true only if the rays of light make small angles with the axis, i.e. strike the mirror close to the pole.  Such rays are said to be paraxial.  Rays outside the paraxial region do not converge to a sharp point, with the result that the image is blurred considerably, a defect known asspherical abberation.  If the image is sharply defined, its location can be found by tracing out the paths of any two rays emanating from O.  One of these may be conveniently chosen to be normal to the mirror, since it is just reflected back along the original path.  Let the other ray strike the mirror at Q, making an angle q with the radius CQ , C being the centre of curvature of the mirror. The image I is located at the intersection of the two reflected rays. We shall assume, for the moment, that OP is greater than the radius of curvature .  Denote by U and V, respectively, the distances of the object and the image I from the pole P.  It follows from the geometry that

 

 

 

 

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