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what is final temperature?
Since the bulb is open,
According to combined gas equation, n1RT1 = n2RT2
Now, n1 = n
And n2 = n + n/4 = 5n/4
T1 = 273 + 19 = 292 K
So, n x R x 292 = (5n/4) x R x T2
So, T2 = (292 x 4)/5
= 233.6 K or -39.4oC