a milk container is made of metal sheet in the shape of frustrum of a cone whose volume is 31380/7 cm3 the radii of its lower and upper circular ends are 8cm and 20cm respectively . find the cost of making the containe
surface area volume
A MILK CONTAINER WILL BE A CLOSED VESSEL SO WE NEED TO TAKE IT'S TSA.
Volume of frustrum = (1/3)πh(r12+r22+r1r2) = 31380/7
(1/3)(22/7)h(202+82+160) = 31380/7
(1/3)(22)h(202+82+160) = 31380
h = 31380x3/(22x624) = 6.86
l = (h2+(r1 - r2)2) = 13.82
TSA of frustrum = πr12 + πr22 + πl(r1+r2) = (3.14)(202+82+(13.83(28)) = 2672 cm2
Cost of making the container = 2672x1.40 = Rs 3740.83.