Question
Fri June 22, 2012 By:

specific conductance of a solution of AgCl in water 1.826*(10 raise to power -6) at 25 degree cel .calculate the solubility of water at 25 degree cel .(conductivity of al is 61.92 and conductivity of Cl 76.3

Expert Reply
Wed July 04, 2012
?m0 AgCl = ? Ag+ + ? Cl-
               = 61.9 +76.3 = 138.2ohm-1cm2mol-1
Solubility = K X 1000 /?0m
             = 1.826 x 10-6 x1000 /138.2
              = 13.2 X 10-6 mol/l
              = 1896.02 x10-6 g/l
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