Question
Fri March 12, 2010 By:

Sir, pl. answer my question

Expert Reply
Fri March 12, 2010

3x=cosecθ  then x = cosecθ/3  and 1/x=cotθ/3

Consider 3(x2-1/x2) = 3( cosec2θ / 9 - cot2 θ/9)

=1/3(osec2θ  - cot2 θ)=1/3 (as cosec2θ - cot2 θ=1)

Sun March 26, 2017

solve

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