Question
Tue November 01, 2011 By:
 

show that the roots of equation x² +px-q²=0 are real for all real values of p and q

Expert Reply
Tue November 01, 2011
Here D = b2 - 4ac = p2 - 4(1)(-q2) = p2 + 4q2
Since p2 and q2 are always positive. D is always positive.
That is D > or = 0.
Hence the roots are real.
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