Question
Fri February 13, 2009 By:

quadrilateral

Expert Reply
Sat February 14, 2009

The sum of the zeroes of a polynomial  in x =-b/a

and

 the product of the zeroes=c/a

 where

 a is coefficient of x squared and b is coefficient of the  term in x and c is the term free of x.

So, here,

a=1, b=-8 and c=k

So sum of the zeroes = -b/a= -(-8)/1=8

product of the zeroes=c/a=k

We need to find the sum of squares of the zeroes.

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