Question
Thu April 07, 2011 By: Saurabh Budholiya
 

prove that the amount of water required to prepare 500 gm of 2.5% solution of glucose is 487.5gm

Expert Reply
Wed May 04, 2011
mass percentage = (mass of solute / mass of solution) * 1oo
2.5 = (mass of solute / 500) * 1oo
mass of solute i.e. glucose = 12.5 g
mass of solution = 500 g
mass of solvent i.e. water = 500 - 12.5 = 487.5 g
 
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