Question
Thu March 25, 2010 By: Hemant Kapoor

Polynomials

Expert Reply
Sun March 28, 2010

x2  - p(x+1) - c

= x2  - px - (p +c)

Comparing with,

x2  - (α + β)x + αβ = 0

α + β = p

αβ = - (p +c)

Now, (α+1)(β+1) = αβ + α + β + 1 = p - p - c + 1 = 1 - c

(α+1)(β+1) = 1 - c

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