Question
Sat April 14, 2012 By: Nihal Sood
 

If three charges q,q and -q are placed at vertices of an equilateral triangle of side L,what is the force on each charge ?

Expert Reply
Sun April 15, 2012
F1 = K q q /L2 = K q2 /L2
 
F2 = K q q /L2 = K q2/L2
 
These are the two forces experienced by the charge (q) by -q and q. But these forces will be opposite in direction because one will be attractive & other will be replusive force.
 
And the angle between them will be 120 degree.
 
So net force will be = F1 Cos 60 + F2 Cos 60 
 
F = K q2/L2 Cos 60 + K q2 /L2 Cos 60 
Thu May 04, 2017

Q)

Home Work Help