Question
Wed September 02, 2009 By:

if momentum increase 50% what is increase in kinetic energy?

Expert Reply
Wed September 02, 2009

Pf = 1.5Pi

Ekf = Pf2/2m

= 1.5Pi2/2m

= 2.25Pi2/2m

= 2.25Eki

Percentage increase in kinetic energy = (Ekf - Eki)x100/Eki = 125%


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