Question
Mon June 06, 2011 By:

For very small angle of projection "a" with horizontal the ratio of RANGE to MAX.HEIGHT of a particle projected upwards with initial speed "u" from ground is ??

Expert Reply
Mon June 06, 2011
As we know that
 
Range of the projectile, R = u2 sin2a / g
 
Max. Height, H = u2 sin2a / 2g
 
R / H = 2 sin2a / sin2a
 
For small angle, sin a = a 
 
R / H = (2 x 2a) / (a x a)
         = 4 / a
Fri May 19, 2017

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