Question
Thu November 15, 2012 By:

find the expansion of(x^2-2x+3)^3 using binomial theorem

Expert Reply
Thu November 15, 2012
(x2-2x+3)3
= [x2-(2x-3)]3
= 3C0(x2)3 - 3C1(x2)2 (2x-3) + 3C2(x2) (2x-3)2 - 3C3 (2x-3)3
Simplify to get the desired result.
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