Question
Sun July 10, 2011 By: Akshaya Parthasarathy

determine the osmotic pressure of 1g of pottasium sulphate in 2l of water at 25 degree celsius assuming tat it is completelf dissociated

Expert Reply
Mon July 11, 2011
Since  K2SO4 is completely dissociated, so i =3

    K2SO 2K+  +  SO4 2-

 = i WB X RT / MB X V

= 3 X 1 X 0.082 X 298 /( 174 X 2)

= 0.211 atm


Home Work Help