Question
Tue February 05, 2013 By:

Answer the following question:

Expert Reply
Thu February 07, 2013

The relative stability of the oxidation states can be analyzed from the electrode potentials. Lower the reduction potential i.e. higher the negative value for M2+|M, higher will be the stability of the +2 oxidation state.

For 3d3 4s2 i.e. Vanadium, Eo = -1.18 so high negative value indicates that +2 state is more stable since it gives half filled t2g3 stable configuration.

For 3d5 4s2 i.e. Manganese, Eo = -1.18 which means that +2 state is more stable since it gives the stable half filled d5 configuration.

For 3d6 4s2 i.e. Iron, Eo = -0.44 so low negative value indicates that +2 is less stable for iron since it can easily lose one more of its electron to attain the half filled stable d5 configuration.

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