Question
Sun June 24, 2012 By: Charchit

an element h bcc structure with the cell edge of 288pm. the dnsity of the element is 7.2g/cm3.how many atom are present in 208g of the element

Expert Reply
Mon June 25, 2012
Edge length is =288pm =288X10-10
Volume of the unit cell = (288X10-10)3
Mass of the element = 208 g
Mass of atom = 208/N
Since it is bcc , number of atoms in a unit cell =2
Mass of unit cell =2x200/N
N= 2x 208/7.2x (288x10-10)3
   = 416/2388 x10-30
=.174x1030
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