Question
Thu December 01, 2011 By: Abhinav Rastogi

A body weighs 63N on the surface of earth. What is the gravitational force on itdue to earth at a height equal to half the radius of earth?

Expert Reply
Thu December 01, 2011
the relation how g varies with  height:
g at height h=g(1+h/R)-2 when h is  comparable with R, if h is very small wrt Rthen
g at height h=g(1-2h/R)
 
here we dont know the height. so we shd apply 1st formula.
 
so, weight at  ht  h=weight at earth surface(1+R/2R)-2
                          =(4/9)×63
                          =28 N
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